![\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{\cfrac{6}{7}}[x-\stackrel{x_1}{(-3)}]\implies y+1=\cfrac{6}{7}(x+3) \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{7}}{7(y+1)=7\left( \cfrac{6}{7}(x+3) \right)}\implies 7y+7=6(x+3)\implies 7y+7=6x+18 \\\\\\ 7y=6x+11\implies -6x+7y=11\implies 6x-7y=-11](/tpl/images/0373/3241/83fa5.png)
6x−5y=−13
6x−7y=11
Mathematics, 14.11.2019 02:31 justkevin1231
What is the equation of this line in standard form?
6x−5y=−13
6x−7y=11
6x−7y=−11
7x−6y=11
Answers: 3
Other questions on the subject: Mathematics
Mathematics, 21.06.2019 20:00, hlannette7005
Segment an is an altitude of right δabc with a right angle at a. if ab = 2, squared 5 in and nc = 1 in, find bn, an, ac.
Answers: 2
Mathematics, 21.06.2019 23:00, mindofnyny
In triangle △abc, ∠abc=90°, bh is an altitude. find the missing lengths. ac=26 and ch=8, find bh.
Answers: 3
You know the right answer?
What is the equation of this line in standard form?
6x−5y=−13
6x−7y=11
6x−5y=−13
6x−7y=11
Questions in other subjects:
