Here is a proof of the theorem with at least one incorrect step. suppose m is any even integer and n is any odd integer. if m · n is even, then by definition of even there exists an integer r such that m · n = 2r. by definition of even and odd, there exist integers p and q such that m = 2p and n = 2q + 1. therefore, by substitution, the product m · n = (2p)(2q + 1) = 2r. but r is an integer by the statement in step 2. thus m · n is two times an integer, so by definition of even, the product is even. identify the mistakes in the proof. (select all that apply.)

this is a very good question

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i got a hair cut today from my mom not to flex just to flex kim jon un is one rad fellow i'd say you'd need to take the hairline in kinda like a box shape like someone rammed a lego brick into your head. from there you really need to take the top up keeping with that boxy aesthetic, finally coat the whole thing with gel if your country economics are failing or whatever you can just coat it with the starving children's food rations. about 5 orphans per strand is a good ratio. good luck with the fresh cut my dude

a

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