The voltage v in a simple electrical circuit is slowly decreasing as the battery wears out. the resistance r is slowly increasing as the resistor heats up. use ohm's law, v = ir, to find how the current i is changing at the moment when r = 465? , i = 0.09a, dv/dt =-0.03v/s, and dr/dt = 0.03? /s. (round your answer to six decimal places.)

The current I is changing at -0.000012.

Step-by-step explanation:

Given : The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's Law, V = IR

To find : How the current I is changing at the moment.

Solution :

We have given,

R = 465\ ohm, I = 0.09A, and

Using Ohm's law, we find V

Re-write ohm's law in terms of I,

Derivate w.r.t to t,

Substitute the values given,

The current I is changing at -0.000012.

step-by-step explanation:

i think it might be a but you might want a second opinion