In the function y=[x]-1, which values of the function are equivalent?

f(-1) and f(-2)

f(1) and f(o)

f(-3) and f(-2.1)

f(2) and f(1.9)

  none of the offered pairs

  f(-2) = f(2)

  f(-1) = f(1)

Step-by-step explanation:

The axis of symmetry of the given function is x=0, so function values will be equivalent only for values symmetrically located about x=0. That is, the function values are equivalent only for opposite values of x.

None of the offered pairs of function values are equivalent.

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.