How much horsepower would the challenger hellcat redeye widebody need to run the speed of sound arrive before the sound of its legendary engine  arrives?

assume stock redeye widebody curb weight

assume no wind

assume no driveline losses

redeye travelling at the speed of sound (760 mph --> 1116.4ft/sec)

hp = fsum x v/hp

f drag = 1/2 pv^2 cda

f rolling resistance = crr x weight

f sum = f drag + f rolling resistance

cd = .398

a = 26.72 ft^2

crr = .015

p= .002377 slugs/ft^3

The answer is based on a curb weight around 4000, you would get

37,834.2 HP

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form