The length, in feet, of a certain structural steel beam is normally distributed with a mean of 8 feet and a standard deviation of 4 inches. quality requirements demand a beam to be rejected if the length is more than 10 inches different from the mean. what percentage of the beams will be rejected? (round your answer to two decimal places.)

The percentage of the beams will be rejected is 1.24%

Step-by-step explanation:

Given information:

Mean, μ = 8 ft

standard deviation, σ = 4 inches

Quality requirements demand a beam to be rejected if the length is more than 10 inches

P = P (- 10/4< z < 10/4)

   = P (-2.5 < z < 2.5)

    = P (z < 2.5) - P(z< -2.5)

    = 0.012419

The percentage of the beams will be rejected is 1.24%

do you mean add both of the equations together

because if you do the answer is 10x-5

step-by-step explanation: