The length of a rectangle is 4 m more than the width. the are is 30 m ^2. find the width and length.

Step-by-step explanation:

AREA FORMULA: LENGTH * WIDTH

L*W=30

L=W+4 thus

(W+4)W=30

W^2+4W=30

W^2+4W-30=0

USING THE QUADRATIC EQUATION WE GET

X=(-B+-SQRT[B^2-4QC])/2A

X=(-4+-SQRT16-4*1*-30])/2*1

X=(-4+-SQRT16+120])/2

X=(-4+-SQRT136)/2

X=(-4+-11.66)/2

X=(-4+11.66)/2

X=7.66/2

X=3.83M IS THE WIDTH.

THUS THE LENGTH IS

L*3.83=30

L=30/3.83

L=7.83M IS THE LENGTH

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

the f

last graph i believe

step-by-step explanation:

worked it out i believe