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y= x2 - 6x + 8

2y + x = 4

the pair of points representing the solution set of this system of equations is

and

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The points of intersections are: (1.5 , 1.25) and (4 , 0)

Step-by-step explanation:

Given:

y = x² - 6x + 8   ⇒ (1)

2y + x = 4         ⇒ (2)

And required the solution of the system of equations.

By graphing the system of equations, the points of intersections are:

(1.5 , 1.25) and (4 , 0)

See the attached figure.

Another solution:

By substitution of y from the second equation at the first equation.

From (1) ⇒ y = 0.5 (4-x)

At (2): and solve for x

0.5 ( 4 - x ) = x² - 6x + 8 ⇒ multiply both sides by 2

4 - x = 2x² - 12x + 16

2x² - 12x + 16 + x - 4 = 0

2x² - 11x + 12 = 0

The general solution of the quadratic equation:

so, a = 2 , b = -11 and c = 12

∴

∴ at x = 4       ⇒ y = 0.5 (4-x) = 0.5 * 0 = 0

And at x = 1.5 ⇒ y  = 0.5 (4-x) = 0.5 * ( 4 - 1.5 ) = 0.5 * 2.5 = 1.25

So, the solution are the points (4,0) and (1.5 , 1.25)

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation: