Saige's spaceship traveled 588588588 kilometers (\text{km})(km)left parenthesis, start text, k, m, end text, right parenthesis in 606060 seconds (\text{s})(s)left parenthesis, start text, s, end text, right parenthesis.
determine whether or not each spaceship trip below has the same speed as saige's spaceship.

has the same speed as saige's spaceship
does not have the same speed as saige's spaceship
441 start text, k, m, end text in 45, start text, s, end text
215 start text, k, m, end text in 25, start text, s, end text
649 start text, k, m, end text in 110 , start text, s, end text give me some answers of edvice to answer the question

the correct answer is 828.07

explanation:

step-by-step explanation:

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.

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