You throw a water balloon straight up with a velocity of 14 m/s. what is it’s max height?

Step-by-step explanation:

The max height of an object can be calculated using one the basic projectile motion equations:

Where:

In this case, let's asumme g=9.8m/s^2, besides θ=90, because the water ballon was threw straight up, so:

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.