Given the relations a: (3,2), (5,3), (6,2), (7,4) which statement is true?

both a and a^-1 are functions

neither a nor a^-1 is a function

only a is a function

only a^-1 is a function

Option 3.

Step-by-step explanation:

The given relation is

A= {(3,2), (5,3), (6,2), (7,4)}

A relation is called a function, if there exist a unique value of y for each value of x.

In relation A, there exist unique output for each input. So, A is a function.

If a relation is defined as R = {(a,b), a∈R,b∈R}, then inverse of R is

R⁻¹ = {(b,a), a∈R,b∈R}

So, inverse of A is defined as

A⁻¹= {(2,3), (3,5), (2,6), (4,7)}

Here, the value of y are 3 and 6 at x=2.

For x=2, there exist more than one output. So, A⁻¹ is not a function.

Therefore, the correct option is 3.

step-by-step explanation:

this woman was an important writer and propagandist during the american revolution. she was a member of the committee of correspondence (in fact the committee was formed in her home) and was an advisor to many of the revolutionary leaders, including george washington and john adams. who was this revolutionary woman?

i believe the answer is c.