If on = 8x – 8, lm = 7x + 4, nm = x – 5, and ol = 3y – 6, find the values of x and y for which lmno must be a parallelogram. the diagram is not drawn to scale. pic and medal

The right answer for the question that is being asked and shown above is that: 

ON = 8x – 8
LM = 7x + 4
NM = x – 5
OL = 3y – 6

OL = NM
3y – 6 = x – 5
3y = x - 6 + 5
3y = x - 1
y = 1/3x - 1/3

ON = LM
8x – 8 = 7x + 4
x = 12
y = 1/3x - 1/3
y = 1/3(12) - 1/3
y = 4 - 1/3
y = 11/3

So the answer is
x = 12
y = 11/3

Sorry can't answer that question