Mathematics, 12.11.2019 03:31 zhellyyyyy
How many solutions does the system have?
\begin{cases} y = -2x-4 y = 3x+3 \end{cases}
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y=−2x−4
y=3x+3
choose 1
choose 1
(choice a)
a
exactly one solution
(choice b)
b
no solutions
(choice c)
c
infinitely many solutions
Answers: 2
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How many solutions does the system have?
\begin{cases} y = -2x-4 y = 3x+3 \end{cases}
...
\begin{cases} y = -2x-4 y = 3x+3 \end{cases}
...
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