Find the product. (–7t – 5v)(–4t – 3v)

a: 28t^2 + 15v^2

b: 28t^2 + 41tv + 15v^2

c: –11t – 8v

d: 28t^2 – 41tv + 15v^2

Option B is the correct answer

Step-by-step explanation:

The given expression is

(–7t – 5v)(–4t – 3v).

The product will be a quadratic equation (having 2 as the highest power)

To find the product, we would expand the brackets

(-7t × -4t )+ (-7t × -3v) + (-5v × -4t) + (-5v × - 3v)

= (- -28t^2) +(- -21tv) + (- - 20tv) +(- -15v^2)

Recall, negative × negative equals positive.

=28t^2 +21tv +20tv+ 15v^2)

Collecting like terms, we add all terms containing the same letters together

28t^2 + 41tv + 15v^2

Option B is the correct answer

dont think so

step-by-step explanation: