Afather is four times as old as his son now. if 5 years later the father is 3 times as old as his son's age. what are their present ages

The Present age of father is 40 years  

The Present age of son is 10 years

Step-by-step explanation:

Given as :

Let the age of father = F years

The age of son          = S years

According to question

F = 4 × S                     1

And  

( F + 5 ) = 3 × ( S + 5 )

F + 5    =  3S + 15

Or,   F - 3S = 15 -5

Or,   F - 3S = 10                 2

From Eq 1 and Eq 2

      4S - 3S = 10

∴      S = 10 years

Put the value of  S in eq 1

So ,  F = 4 × S   = 4 × 10

∴      F = 40  years

Hence The Present age of father is 40 years  

And      The Present age of son is 10 years    Answer

the given 6 = w/p is equivalent to 6p = w, where w is the total area of the walls and p is the area covered by a single can of paint.

knowing that 6 cans of paint will be needed, 6p = w becomes 6(6) = w = 36.   this tells us that the total area to be painted is 36 square units.