Given the equation square root of 2x-1=7 solve for x and identify if it is an extraneous solution. i came up with the answer 25 but is it an extraneous solution?

Step-by-step explanation:

To check if a solution is extraneous, simply plug it back into the original equation.  If it works, then solution isn't extraneous.

√(2x−1) = 7

√(2(25)−1) = 7

√(50−1) = 7

√(49) = 7

7 = 7

So the solution isn't extraneous.

1: -2 3/4, -2 1/2, -14, 0, 3, 8 1/3

2: -4, -3, -2 1/2, -2 1/4, 3 1/4,

step-by-step explanation: