Find an equation of the line that passes through (0,2) and is parallel to y= 1/2x +6

y= 1/2x +2

Step-by-step explanation:

y-2 = 1/2(x-0)

y-2= 1/2x

y= 1/2x + 2

y=1/2x+2

Step-by-step explanation:

1/2 is your slope

2=y intercept

its a positive slope

y=mx+b

y=1/2x+2

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15