The length of the rectangle is twice its width. write and solve a system of linear equations to find the length l and width w of the the perimeter is 36 ft

2 ( m + 2 m)  = 36 is the required linear equation

Length of the rectangle is 12 ft and width =  6 ft

Step-by-step explanation:

Let the width of the rectangle = m ft.

So, the length of the rectangle = 2m  ft.

Perimeter  of rectangle = 36 ft

Now, PERIMETER OF THE RECTANGLE = 2(LENGTH + WIDTH)

⇒2 ( m + 2m)  = 36

or, 2 x 3m  = 36

⇒ 6m  = 36  , or m  = 36/6

⇒ m  =6 ft

So, the Width of the rectangle;  =  m = 6 ft

and the Length of the rectangle  = 2 m  = 2 x 6 =  12 ft.

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk

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