Combinatorics is a branch of math focused on arrangements of objects. jorge is and event organizer who must seat 102 guests. he has circular tables that seat 10 people each and square tables that seat 4 people each. he wants to use as many circular tables as possible but have no empty seats. explain how he could arrange the tables he will need. if you don’t mind may you also tell me what real-world-knowledge you used to understand this stem task and what strategies or methods you used from your previous learning did you use to complete the stem task. god bless!

the answer is 37

step-by-step explanation:

you cant answer this dummy

step-by-step explanation:

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.