The perimeter of a rectangular sports court is 134 feet. after a game, a player's coach estimates that the athlete has run a total of 378 feet, which is equivalent to four times the court's length plus nine times its width. what are the dimensions of the sports court?

45ft by 22ft

Step-by-step explanation:

perimeter is 2L+2W =134ft

The coach says that 378=4L+9W

We can rearrange the first equation to get L=67-W, then solve by substitution.

378=4(67-W)+9W=268+5W

110=5W so W=22

L=67-W and W=22 so

L=67-22=44

Therefore the dimensions are 22 by 45

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.