An individual uses the following gambling system at las vegas. he bets $ 1 that the roulette wheel will come up red. if he wins, he quits. if he loses then he makes the same bet a second time only this time he bets $ 2; and then regardless of the outcome, quits. assuming that he has a probability of 12 of winning each bet, what is the probability that he goes home a winner? why is this system not used by everyone?

3/4

Step-by-step explanation:

Given that an individual uses the following gambling system at Las Vegas. He bets $ 1 that the roulette wheel will come up red

Prob of winning in one trial = 1/2

For him to go home as winner either he has to win in the I case or he loses I one and wins the second one.

Hence probability = prob he wins the Ist +prob he loses first and wins second

=

This system will not be used because normally prob of winning will not be 1/2 but much more less than that.  Hence prob of losing would be more so everyone may not use this.

go and ask your mom to you

the car was traveling 40 mph before it started skidding. ( 2 points ) 17. was the driver were her brakes working at 75% efficiency or better? ( 2 points ) yes 29.

step-by-step explanation: