(problem of the week)
in a rock-paper-scissors game, a winner gets
5 points and a loser gets 2 points. after a man
played this game 20 times, his total score was
67 points. how many times did he win, and
how many times did he lose?

He won 13 times and lost 1 time

Step-by-step explanation:

divide 67 by 5 so 67÷5 you would get 13.4 you take the whole number 13 and multiply it by 5 and that will get you to 65 so then you only have 2 left over and if you lose you get 2 point so therefore you know that he lost only once

(13•5)+2=67

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

hello,

b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

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