An arrow is shot vertically upward at a rate of 170 feet per second from ground level.

*look at photo attached for the complete

t1= 1.1475 sec

t2=9.48 sec

Step-by-step explanation:

This question asking for the time when an object reach a specific height. I will explain what the formula stand for to make this easier.

h= height = 174feet

v0= initial velocity = 170 feet/s

t= time

h0= initial height= ground level = 0

The question have predetermined formula for the height, so we should use it instead of formula that involve gravity value.

h= -16 +v0t + h0t

174 feet = -16 + 170 feet/s x t + 0 x t

-16 + 170 feet/s x t  - 174 feet = 0

8 - 85 feet/s x t  + 87 feet = 0

This equation will be hard to solve since its value in fraction, so lets use the quadratic formula

t1=

t1= 1.1475

t2=

t2=9.48

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.