Acube made of silver has a density of 10,490 kg/m^3 if one of the sides were doubled without changing the mass of silver how would the density of the cube be changed?

Density will be half of the original density and is equal to 5245 kg/m³

Step-by-step explanation:

Given:

Density of the cube is,

Let the side of the cube be m.

Volume of the cube,

If one side of the cube is doubled, the resulting figure is a cuboid with dimensions

So, new volume is,

Density is given as,

If mass is constant, then density is inversely proportional to its volume.

Therefore,

So, the density of a constant mass is exactly half the original density when one of its sides is doubled.

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."