The difference of the product of the polynomials a^2+7a–4 and a–2 and the polynomial a^3+4a^2–29a+11

Step-by-step explanation:

(a²+7a–4)  * (a–2) =  (a²+7a–4)* a - (a²+7a–4) *2

     = a²*a + 7a*a - 4*a  - a²*2  - 7a *2 + 4 *2

    = a³ +7a² - 4a - 2a² - 14a +8

=  a³ + 5a² - 4a - 14a +8

= a³ + 5a² - 18a +8

a³ + 5a² - 18a +8 - (a³+4a²–29a+11) =a³ + 5a² - 18a +8 -a³- 4a²+29a - 11

= a² + 11a - 3

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

angle efh= angle egh