The table represents the height of a ball that is dropped, h(t), after t seconds. a 2-column table with 6 rows. the first column is labeled x with entries 0, 1, 2, 3, 4, 5, 6. the second column is labeled h(t) with entries 150, 145.1, 130.4, 105.9, 71.6, 27.5, negative 26.4. determine the initial height of the ball and the time interval before the ball hits the ground. initial height = 0; hits the ground between 5 and 6 seconds initial height = 150; hits the ground between 5 and 6 seconds initial height = 0; hits the ground between 3 and 4 seconds initial height = 150; hits the ground between 4 and 5 seconds

initial height = 150; hits the ground between 5 and 6

Step-by-step explanation:

The table represents the height of a ball that is dropped, h(t), after t seconds.

The first column is labeled x with entries 0, 1, 2, 3, 4, 5, 6. The second column is labeled h(t) with entries 150, 145.1, 130.4, 105.9, 71.6, 27.5, negative 26.4.

The table is shown below

x (seconds h(t)

0. 150

1. 145.1

2. 130.4

3. 105.9

4. 71.6

5. 27.5

6. -26.4

From the table,

At time if 3 seconds, the ball has not moved. So the initial height is 150.

As the ball was dropped, it started moving and the height kept on reducing from 150 to -26.4 with increasing time.

Between 5 and 6 seconds, the ball hits the ground and probably dug went beyond the surface of the ground hence, the negative value

Step-by-step explanation:

The given table is

t      h(t)

0     150

1     145.1

2    130.4

3    105.9

4     71.6

5     27.5

6    -26.4

The initial height is 150 units, because it's at t = 0, which is the initial point.

The time interval when the ball hits the ground is 5-6. You can deduct this by looking the interval which contains the transition from positive to negative, and that is the last interval.

Therefore, the right answer is the last choice.

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct