Jamir is buying tablets and laptops for a computer lab. he represents the number of tablets (x) and laptops (y) that he can buy with the system of inequalities given.

130x+250y≤3600
x> 5
y> 9
enter the maximum number of tablets that he can purchase to satisfy the system of inequalities.

me understand how do answer this to some degree! or at the very least tell me how you got the answer. i need the brainliest person for this one.

8 tablets.

Step-by-step explanation:

There has to be at least 10 laptops, because 10 is the smallest whole number that is greater than 9. 10 laptops is equal to 250 * 10 = $2500. Therefore, we do 3600 - 2500 to get 1100. this means we have 1100 dollars left. Next, i figure out what is the most tablets you can get. It's 8 because 9 tablets

(130 * 9) is equal to 1170, and 1170 is not equal to/less than 1100, so 8 is the greatest amount.

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.