Abook can be classified as either non dash fiction or fiction. suppose that 87% of books are classified as fiction. (a) two books are chosen at random. what is the probability that both books are fiction? (b) four books are chosen at random. what is the probability that all four books are fiction? (c) what is the probability that at least one of four randomly selected books is non dash fiction? would it be unusual that at least one of four randomly selected books is non dash fiction?

0.7569, 0.5729,0.4371

Step-by-step explanation:

Given that the books are of only two types either non dash fiction or fiction.

Also probability of selecting a fiction = 0.87 = p

X - no of books fiction selected is binomial with p = 0.87 and n =2

(since each trial is independent of the other and there are only two trials)

a) the probability that both books are fiction=

b) Here n =4 with same p.

c) Prob atleast one is non dash  fiction =

This is not unusual since 0.4371 probability is not nearer to 0 it is almost half.

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0