Atrucker hauls citrus fruit from florida to montreal. each crate of oranges is 4 ft3 in volume and weighs 60 lb. each crate of grapefruit has a volume of 6 ft3 and weighs 75 lb. his truck has a maximum capacity of 300 ft3 and can carry no more than 4800 lb. moreover, he is not permitted to carry more crates of grapefruit than crates of oranges. if his profit is $2.50 on each crate of oranges and $4 on each crate of grapefruit, how many crates of each fruit should he carry for maximum profit?

answer:

3 bags of apples and 2 bags of oranges.

step-by-step explanation:

(5x-1)^2= (5x)^2-2(5x)×1+(1)^2=25x^2-10x+1

24,18t

step-by-step explanation:

secant-secant formula:

(whole secant) x (external part) =           (whole secant) x (external part)

(8+y-2) *8=                                           (y+4+6) *6

(y+6)*8 = (y+10) *6

distribute

8y+48 = 6y +60

subtract 6y from each side

2y +48 = 60

subtract 48 from each side

2y = 12

divide by 2

y = 6

sv =     (y+4+6)

sv   = 6+4+6

sv = 16