The perimeter of a rectangle is 58. the length is 1 more than 2 1/2 times the width. find the dimensions of the rectangle

The formula of the perimeter of a rectangle is given as

P=2L+2W

where L is the length and W is the width. Substitution of the given values will yield,

58=2L+2W     (1)

The next thing that we have to do is to translate the relationship between the two variables, L and W, into a mathematical equation.

So we have 

L=2.5W+1     (2)

Now we have two equations, we also have two unknowns, so this problem is solvable. Substitution of equation (2) in (1) yields

58=2(2.5W+1)+2W
58=5w+2+2w
58=7W+2
56=7W
8=W

Substitution of this value to equation (2) yields

L=2.5(8)+1
L=21

So, the dimensions of the rectangle are:, specifically, width is equal to 8 while length is equal to 21.

Omg that is a big question and weird words and i’m only 5

Ireally don’t understand your problem do you have a better picture of it