1. complete the paragraph proof.
given: le bisects l and le i gu
prove: aleg aleu
le bisects zl is given. zgle is congruent to zule by the definition of an
le is congruent to le by the
property of congruence. le is perpendicular to gu is given, so zgel and xuel are right
angles by the
_. therefore,
lgel is congruent to lleu because
_ are congruent.
so, aleg = aleu by

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

the answer is d

for problems like this theres an app, its photomath that explains the problem and gives the answer hope i

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step-by-step explanation:

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