Carla has a store that sells candles for 4 for 10 dollars. how many candles will she need to make 100 dollars?
i need the answer quick

She will need 40 candles to make 100 dollars

Step-by-step explanation:

Step 1: Determine price per unit of candle

The price per unit of candle can be expressed as;

Price per unit=Total cost of candles/Number of candles sold

where;

Total cost of candles=10 dollars

Number of candles sold=4

replacing;

Price per unit=10/4=2.50 dollars

This means that 1 candle will be sold for 2.50 dollars

Step 2: Number of candles needed to make 100 dollars

Number of candles sold=Total cost of candles/Price per unit

where;

Total cost of candles=100 dollars

Price per unit=2.5 dollars per candle

replacing;

Number of candles sold=(100/2.5)=40

She will need 40 candles to make 100 dollars

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.

it would be a on edgenuit y

the diagram below is your final answer