Afence is to be built to enclose a rectangular area of 800 square feet. the fence along three sides is to be made of material that costs $5 per foot. the material for the fourth side costs $15 per foot. find the dimensions of the rectangle that will allow for the most economical fence to be built.

dc/dx = 0 when x = 20. hence fence is 20×40

Step-by-step explanation:

Given data:

Rectangular Area = 800 ft^2

three side material cost = $5 per ft

fourth side material cost is $15 per ft

let expensive side is x and other dimension assume to be y

Then cost is c

c = 5(x+ 2y) + 15 x

xy = 800, so y = 800/x

c =5(x+ 1600/x^2) + 15x

for minimum when dc/dx = 0

(2x-40)(2x+40) = 0

x = 20

dc/dx = 0 when x = 20. hence fence is 20×40

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x