The anterior cruciate ligament (acl) runs diagonally in the middle of the knee. an article reported results for 85 young athletes who suffered anterior cruciate ligament (acl) injuries. of the 85 injuries, 53 were to the left knee and 32 were to the right knee. can you conclude that more than half of acl injuries are to the left knee? find the p-value and state a conclusion.

The left knee injuries are more than half.

Step-by-step explanation:

Given that the anterior cruciate ligament (ACL) runs diagonally in the middle of the knee.

Sample size n = 85

left knee = 53

p = Sample proportion =

(Right tailed test)

p difference = 0.124

std error =

Test statistic z = 2.28

p value = 0.01130

Since p <0.05, at 5% level we reject H0.

The left knee injuries are more than half.

2x^2+5x+17

your welcome. : )

2 & 7

step-by-step explanation:

he climbs 300 ft/hr at a constant rate. the peak is at 1,500 ft.

when going up, he reaches 600 ft in 2 hours. remember, that he is going in a constant rate. divide 600 with 300:

600/300 = 2

assuming that he takes the same route back (meaning that it's a 1500 ft route back, you can solve.

note also that you are solving when he gets back to 600 ft after he reaches the peak.

first, find the amount of hours it takes to get up the peak. divide the total amount (1500), with the ft/her (300) to get the amount of hours (x):

1500/300 = x

x = 5

it takes jamie 5 hours to get up. now, he is returning down, and reaches 600 (his current destination). remember that he climbs at a constant 300 ft/hr. divide 600 with 300:

600/300 = x

x = 2

now add the two numbers together.

x = 5 + 2 = 7

jamie takes 7 hours to go up the mountain and reach his current position when descending.

(total amount/constant rate) = (time).

remember that it is a constant rate, so in total, when he gets back down the mountain, it will take the same amount of time as when he goes up. the total amount for the round trip is: 5 + 5 = 10.

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