Which of the following completes the proof?

triangles abc and edc are formed from segments bd and ac, in which point c is between points b and d and point e is between points a and c.

given: segment ac is perpendicular to segment bd

prove: δacb ~ δecd

reflect δecd over segment ac. this establishes that then, this establishes that ∠e'd'c' ≅ ∠abc. therefore, δacb ~ δecd by the aa similarity postulate.

∠abc ≅ ∠e'd'c'; translate point e' to point a
∠acb ≅ ∠e'c'd'; translate point e' to point b
∠acb ≅ ∠e'c'd'; translate point d' to point b
∠abc ≅ ∠e'd'c'; translate point d' to point a

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

lo98765432wqasdfghjkloi87654567890

step-by-step explanation: