Abank loaned out $37,500, part of it at the rate of 11% annual interest, and the rest at 9% annual interest. the total interest earned for both loans was $3,745.00. how much was loaned at each rate?

The Loan amount at 11 % interest rate is $ 18,500   And

The Loan amount at 9 % interest rate is $ 19,000

Step-by-step explanation:

Given as :

Let The loan given at interest rate of 11 % annual  = $ x

And The loan given at interest rate of 9 % annual = ($37,500 - $ x)

Total interest fro both loan = $3745

I.e  CI 1 + CI 2 = $3745

Now, From compound interest method :

Or,  A 1 = $ 1.11 x

Similarly

Or, A 2 = 1.09 × ($37,500 - $ x)

∵  Compound Interest = Amount - principal

Or, $ 3745 = CI 1 + CI 2

Or,  $ 3745 = ($ 1.11 x - $ x) + ( 1.09 × ($37,500 - $ x) -  ($37,500 - $ x) )

Or,  $ 3745 = $ .11 x+  ($37,500 - $ x) ( .09 )

Or,  $ 3745 = $ .02 x + $ 3375

or,  0.02 x =  $ 3745 - $ 3375

∴   x = $

SO,  x = $ 18,500

And $ 37500 - x = $ 19,000

Hence The Loan amount at 11 % interest rate is $ 18,500   And

           The Loan amount at 9 % interest rate is $ 19,000   Answer

step-by-step explanation:

what grade level is this? need to know so i can look in my old textbooks!

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.