Gianna invested $30,000 in an account paying an interest rate of 1.9% compounded
annually. assuming no deposits or withdrawals are made, how much money, to the
nearest ten dollars, would be in the account after 8 years?

5,095,068

Step-by-step explanation:

The equation for this problem is x^y * z where x is the percentage, Y is the number of years, and Z is the original deposit. Multiply 1.9^8 * 30,000 which becomes; 5,095,068.

Whoever has that bank account is going to be very rich.

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.

a precentage of 6th graders. the population is all 6th graders. let me know if i'm wrong, i hope this ! : )

step-by-step explanation: