Twice the difference of a number and 4 is equal to three times the sum of the number and 5 find the number

Twice the difference of a number and 4 is equal to three times the sum of the number and 5

number - N

find the number

2(N - 4) = 3(N + 5)

2N - 8 = 3N + 15

-15 - 8 = 3N - 2N

- 23 = N

Check

2(N - 4) = 3(N + 5)

2(-23 - 4) = 3(-23 + 5)

2(-27) = 3(-18)

-54 = -54

$25

step-by-step explanation:

25 - 4.50 = 20.5

20.5 / 2 = 10.25

10.25 + 10 = 20.25

20.25 - 12.50 = 7.75

therefore the answer is $25 as shown as the first number.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15