If you roll two fair six-sided dice, what is the probability that at least one die shows a 333?

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explanation:

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol

answer: what are the following choices

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube