Acandidate for mayor in a small town has allocated $40,000 for last-minute advertising in the days preceding the election. two types of ads will be used: radio and television. each radio ad costs $200 and reaches an estimated 3,000 people. each television ad costs $500 and reaches an estimated 7,000 people. in planning the advertising campaign, the campaign manager would like to reach as many people as possible, but she has stipulated that at least 10 ads of each type must be used. also, the number of radio ads must be at least as great as the number of television ads. how many ads of each type should be used? how many people will this reach? let x1= the number of radio ads purchasedx2= the number of television ads purchasedmaximize3,000x1+7,000x2(ma ximize exposure)subject to: 200x1+500x2≤40,000(budget constraint)x1≥10(at least 10 radio ads purchased)x2≥10(at least 10 television ads purchased)x1≥x2(# of radio ads ≥ # of television ads)x1, x2≥0(non-negativity constraints)

Step-by-step explanation:

Radio ads reach 3000/200 = 15 people per dollar.

Television ads reach 7000/500 = 14 people per dollar.

Except for the constraints on the number of TV ads, the best value for the advertising dollar comes from radio ads.

So, we must satisfy the constraint that 10 TV ads are the minimum. Then the remaining 35,000 in advertising budget can be spent on 175 radio ads. The number of people reached by this advertising will be ...

  175·3000 +10·7000 = 595,000 . . . people

10 TV ads and 175 radio ads should be used. This campaign will reach 595,000 people.

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This graph is drawn so the feasible region is white. Areas outside the feasible region are shaded. (This approach can make identifying the feasible region easier.) The object is to get the objective function line as far from the origin as possible. The feasible region vertex (175, 10) does that.

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation:

2 & 7

step-by-step explanation:

he climbs 300 ft/hr at a constant rate. the peak is at 1,500 ft.

when going up, he reaches 600 ft in 2 hours. remember, that he is going in a constant rate. divide 600 with 300:

600/300 = 2

assuming that he takes the same route back (meaning that it's a 1500 ft route back, you can solve.

note also that you are solving when he gets back to 600 ft after he reaches the peak.

first, find the amount of hours it takes to get up the peak. divide the total amount (1500), with the ft/her (300) to get the amount of hours (x):

1500/300 = x

x = 5

it takes jamie 5 hours to get up. now, he is returning down, and reaches 600 (his current destination). remember that he climbs at a constant 300 ft/hr. divide 600 with 300:

600/300 = x

x = 2

now add the two numbers together.

x = 5 + 2 = 7

jamie takes 7 hours to go up the mountain and reach his current position when descending.

(total amount/constant rate) = (time).

remember that it is a constant rate, so in total, when he gets back down the mountain, it will take the same amount of time as when he goes up. the total amount for the round trip is: 5 + 5 = 10.

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