What function describes a line with slope 4/3 and passing through the point (2,5) ?

The answer is: f(x) = 4/3x + 7/3

Step-by-step explanation:

Start with the point slope form of the equation:

y - y1 = m(x - x1)

y - 5 = 4/3(x - 2)

y - 5 = 4/3x - 8/3

y = 4/3x - 8/3 + 5

y = 4/3x - 8/3 + 15/3

y = 4/3x + 7/3

Replace y with f(x):

f(x) = 4/3x + 7/3

proof:

f(2) = 4/3 * 2 + 7/3

= 8/3 + 7/3 = 15/3 = 5

hello, sorry being so rude after all that fighting i found it kind of funny, so as me saying sorry here is an answer!

since the table showed her that   2km = 2000m.

to determine, how many km in 2000m, she would divide by 1000.

= 2000 / 1000 = 2 km.

similarly, for 8000m = 8000 / 1000 = 8 km

cheers to savings

~

your pal papaguy