The base bc of isosceles triangle abc is extended
through c to d. if mlacd = 108, what is
the number of degrees in the measure of vertex
angle a ?

angle of A is 36°

Step-by-step explanation:

ACB = 180° - ACD ( angle in a straight line is 180°)

= 180° - 108°

= 72°

ACB = ABC (isoceles triangle)

BAC = 180° - ACB - ABC (angle in a triangle is 180°)

= 180° - 72° - 72°

= 36°

(Correct me if i am wrong)

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right