Write an equation of a parabola in vertex form. vertex (2,-3) and passes through (0,5)

Step-by-step explanation:

The vertex form of a parabola is given by  y = a(x - h)^2 + k, where (h, k) is the vertex.

Given vertex at (2,-3), h = 2, k = -3

y = a(x - 2)^2 + (-3) = a(x - 2)^2 - 3

The parabola passes through (0,5) so

5 = a(0 - 2)^2 - 3

5 = 4a - 3

4a = 8

a = 2

The parabola equation in vertex form:

y = 2(x - 2)^2 - 3

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier

16

step-by-step explanation: