Aradio signal travels at 3.00 • 10^8 meters per second. how many seconds will it take for a radio signal to travel from a satellite to the surface of earth if the satellite is orbiting at a height of 3.54 • 10^7 meters? show your work.
would the answer be rate=3*10^8m/s
distance=3.6*10^7m
time=distance/rate=3.6/30

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.