A40-foot ladder is leaning against a building and forms a 29.32° angle with the ground. how far away from the building is the base of the ladder? round your answer to the nearest hundredth.

The base of the ladder is 34.80 ft away.

Solution:

Given, Length of the ladder is 40 ft; The angle formed by ladder on ground

A right angle triangle is formed with hypotenuse is 40 ft, angle is and to find base (adjacent) is b.

The trigonometric function to find the missing side of the right angled triangle is

Therefore, the distance between the base of the ladder and the building is 34.8 ft.

Rounding 34.8 to the nearest hundred gives the value 34.80.  

The ladder inclined to the wall of the building and its length is 20ft. The ladder forms a 72° angle with the ground. 

We are asked to solve for the distance of the base of the ladder to the building. Thus, we can use SOH CAH TOA and we have the solution below:

cos 72°=adjacent/20ft

adjacent=20*cos72°

adjacent=6.18 feet

The distance is 6.18 feet.

6. 104

7. 52/37

8. 2704

9. 140608

10. -52

11. |52|=52

12. 1/52

13. 156

14. 26

15. 40

16. 37

17. -364

18. 53 1/3

19. 50.96

20. 43 2/3

21. 78

22. 50.75

23. 47.63

24. 163.28

25. 10400

26. 338

27. 208

28. 2704 square inches

29. 312 square meters

30. don't know what its asking, tell me so i can tell you

31. 8490.56

32. 52 degrees would be an acute angle

33. 128 degrees

34. 20.8

35. 39

36. 208