What is the equation of a line that is parallel to the line 2x + 5y = 10 and passes through the point (–5, 1)? check all that apply. y = −two-fifthsx − 1 2x + 5y = −5 y = −two-fifthsx − 3 2x + 5y = −15 y − 1= −two-fifths(x + 5)

2x + 5y = -5

Step-by-step explanation:

Since the new line is parallel to the given line 2x + 5y = 10, the equation of the new line has exactly the same form as does 2x + 5y = 10, except that the constant will be different.

Were we to solve this equation (in standard form) for y in slope-intercept form, we'd get:

5y = -2x + 10, or

        -2x + 10

y =

              5

or

y =  (-2/5)x + 2

Writing out 2x + 5y = C, we substitute -5 for x and 1 for y, obtaining

2x + 5y = C  =>  2(-5) + 5(1) = -10 + 5 = -5.  Therefore, C = -5 and the equation of the new line is

2x + 5y = -5

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.