Ashipment of 1000 small lab mice arrives at the animal care facility. we wish to estimate the actual mean weight of the mice. a simple random sample of 100 mice is selected and weighed, and the resulting 95% confidence interval for the actual mean weight is from 9.9 to 10.5 gram. using the same data to test the hypotheses about the actual mean weight, which of the following is correct? we cannot reject the hypothesis that the sample mean is 10.2 gram at α = 0.05 we cannot reject the hypothesis that 95% of individual mice weight between 9.9 and 10.5 gram we can reject the hypothesis that the true mean is 10 gram at α = 0.05 we can reject the hypothesis that the true mean weight is 11 g versus that the mean weight is not equal to 11 gram at α = 0.05

Step-by-step explanation:

We cannot reject the hypothesis that the sample mean is 10.2 gram at α = 0.05

True . Given the confidence interval from 9.9 to 10.5 gram, we can conclude that true population mean can be estimated 10.2±0.3 in 95% confidence.

We cannot reject the hypothesis that 95% of individual mice weight between 9.9 and 10.5 gram

False. Confidence interval is an estimation about the population mean, not about the indivudual samples.

We can reject the hypothesis that the true mean is 10 gram at α = 0.05

False. We cannot reject this hypothesis sice 10 gram is in the confidence interval at 0.05 significance

We can reject the hypothesis that the true mean weight is 11 g versus that the mean weight is not equal to 11 gram at α = 0.05

True. According to the sample results 11 gram is out of the confidence interval in 95 confidence level. Therefore we can reject the hypothesis that true mean weight is 11 g.

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841