Choose the linear inequality that describes each graph.

y > – 5x + 3

y > – 5x – 3

y < – 5x + 3

y > – 3x + 5

Step-by-step explanation:

Starting from the y-intercept of you do by either moving five blocks north over one block west or five blocks south over one block east [west and south are negatives], then you shade everything to the right of the line because using the zero-interval test, also known as the test point [origin], we can determine what side of a line to shade. This is done by plugging "0" in for both y and x, then determining whether false or true will tell you which side to shade. In this case, we shade to the right of the line because when we plug the test point into the function, we get this false statement:

So, we do not want to shade the side with the origin. We would want to shade the OPPOSITE side, which is what you see in the graph.

I am joyous to assist you anytime.

* In this case, do not worry about whether to use dashed or solid lines because since your inequality symbol is a greater than symbol, that already tells you that you need a dashed line, otherwise it would be solid if it were a greater than or equal to symbol [≥].

** Picking ANY point in the shaded region of a linear inequality equation will ALWAYS make an authentic statement.

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

step-by-step explanation:

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