The total surface area of a cylinder is 690.8
inches. its diameter is 10 inches. what is its
height?

Height = 16.99 inches.

Step-by-step explanation:

We know, the surface area of a cylinder = 2πrh + 2πr^2

Given,

Diameter of a cylinder, 2r = 10 inches

r = 5 inches

According to the question,

2πrh + 2πr^2 = 690.8

or, 2r*π*h + 2(r^2)*π = 690.8

or, 10*3.1416*h + 2(5^2)*3.1416 = 690.8

or, 31.416h + 157.08 = 690.8

or, 31.416h = 690.8-157.08

or, 31.416h = 533.72

or, h = 533.72/31.416

or, h = 16.99

Therefore, the height of the cylinder is 16.99 inches.

-4

step-by-step explanation:

(-4+8)=-(4-8)=-8+4=-4

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47