Anews agency publishes results of a recent poll. it reports that candidate a leads candidate b by 10% because 45% of the poll participants supported ms. a whereas only 35% supported mr. b. what margin of error should be reported for each of the listed estimates, 10%, 35%, and 45%? notice that 900 people participated in the poll, and the reported margins of error typically correspond to 95% confidence intervals.

We need to use the formula to find Margin of Error but through the sample proportion, that is

We will use a 95% confidence interval, that is a z value of 1.96 (Search in a Normal distribution table)

A) For A our (proportion) is equal to 0.45. So applying the formula,

B) We make the same of point A, but change our proportion to 0.35

c) We need to calculate the SE through proportion for 0.1, that is

Then our Error is given by,

addition

step-by-step explanation:

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